215x-16x^2-97=0

Solution for 215x-16x^2-97=0 equation:

215x-16x^2-97=0

a = -16; b = 215; c = -97;
Δ = b2-4ac
Δ = 2152-4·(-16)·(-97)
Δ = 40017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(215)-\sqrt{40017}}{2*-16}=\frac{-215-\sqrt{40017}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(215)+\sqrt{40017}}{2*-16}=\frac{-215+\sqrt{40017}}{-32}
$